Integrand size = 12, antiderivative size = 143 \[ \int \frac {1}{(a+a \cos (c+d x))^5} \, dx=\frac {\sin (c+d x)}{9 d (a+a \cos (c+d x))^5}+\frac {4 \sin (c+d x)}{63 a d (a+a \cos (c+d x))^4}+\frac {4 \sin (c+d x)}{105 a^2 d (a+a \cos (c+d x))^3}+\frac {8 \sin (c+d x)}{315 a d \left (a^2+a^2 \cos (c+d x)\right )^2}+\frac {8 \sin (c+d x)}{315 d \left (a^5+a^5 \cos (c+d x)\right )} \]
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Time = 0.11 (sec) , antiderivative size = 143, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {2729, 2727} \[ \int \frac {1}{(a+a \cos (c+d x))^5} \, dx=\frac {8 \sin (c+d x)}{315 d \left (a^5 \cos (c+d x)+a^5\right )}+\frac {8 \sin (c+d x)}{315 a d \left (a^2 \cos (c+d x)+a^2\right )^2}+\frac {4 \sin (c+d x)}{105 a^2 d (a \cos (c+d x)+a)^3}+\frac {4 \sin (c+d x)}{63 a d (a \cos (c+d x)+a)^4}+\frac {\sin (c+d x)}{9 d (a \cos (c+d x)+a)^5} \]
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Rule 2727
Rule 2729
Rubi steps \begin{align*} \text {integral}& = \frac {\sin (c+d x)}{9 d (a+a \cos (c+d x))^5}+\frac {4 \int \frac {1}{(a+a \cos (c+d x))^4} \, dx}{9 a} \\ & = \frac {\sin (c+d x)}{9 d (a+a \cos (c+d x))^5}+\frac {4 \sin (c+d x)}{63 a d (a+a \cos (c+d x))^4}+\frac {4 \int \frac {1}{(a+a \cos (c+d x))^3} \, dx}{21 a^2} \\ & = \frac {\sin (c+d x)}{9 d (a+a \cos (c+d x))^5}+\frac {4 \sin (c+d x)}{63 a d (a+a \cos (c+d x))^4}+\frac {4 \sin (c+d x)}{105 a^2 d (a+a \cos (c+d x))^3}+\frac {8 \int \frac {1}{(a+a \cos (c+d x))^2} \, dx}{105 a^3} \\ & = \frac {\sin (c+d x)}{9 d (a+a \cos (c+d x))^5}+\frac {4 \sin (c+d x)}{63 a d (a+a \cos (c+d x))^4}+\frac {4 \sin (c+d x)}{105 a^2 d (a+a \cos (c+d x))^3}+\frac {8 \sin (c+d x)}{315 a^3 d (a+a \cos (c+d x))^2}+\frac {8 \int \frac {1}{a+a \cos (c+d x)} \, dx}{315 a^4} \\ & = \frac {\sin (c+d x)}{9 d (a+a \cos (c+d x))^5}+\frac {4 \sin (c+d x)}{63 a d (a+a \cos (c+d x))^4}+\frac {4 \sin (c+d x)}{105 a^2 d (a+a \cos (c+d x))^3}+\frac {8 \sin (c+d x)}{315 a^3 d (a+a \cos (c+d x))^2}+\frac {8 \sin (c+d x)}{315 d \left (a^5+a^5 \cos (c+d x)\right )} \\ \end{align*}
Time = 0.12 (sec) , antiderivative size = 89, normalized size of antiderivative = 0.62 \[ \int \frac {1}{(a+a \cos (c+d x))^5} \, dx=\frac {\cos \left (\frac {1}{2} (c+d x)\right ) \left (126 \sin \left (\frac {1}{2} (c+d x)\right )+84 \sin \left (\frac {3}{2} (c+d x)\right )+36 \sin \left (\frac {5}{2} (c+d x)\right )+9 \sin \left (\frac {7}{2} (c+d x)\right )+\sin \left (\frac {9}{2} (c+d x)\right )\right )}{315 a^5 d (1+\cos (c+d x))^5} \]
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Result contains complex when optimal does not.
Time = 0.78 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.48
method | result | size |
risch | \(\frac {16 i \left (126 \,{\mathrm e}^{4 i \left (d x +c \right )}+84 \,{\mathrm e}^{3 i \left (d x +c \right )}+36 \,{\mathrm e}^{2 i \left (d x +c \right )}+9 \,{\mathrm e}^{i \left (d x +c \right )}+1\right )}{315 d \,a^{5} \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )^{9}}\) | \(69\) |
derivativedivides | \(\frac {\frac {\left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{9}+\frac {4 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{7}+\frac {6 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5}+\frac {4 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3}+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{16 d \,a^{5}}\) | \(71\) |
default | \(\frac {\frac {\left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{9}+\frac {4 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{7}+\frac {6 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5}+\frac {4 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3}+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{16 d \,a^{5}}\) | \(71\) |
parallelrisch | \(\frac {35 \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+180 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+378 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+420 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+315 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{5040 a^{5} d}\) | \(73\) |
norman | \(\frac {\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{16 d a}+\frac {\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )}{12 d a}+\frac {3 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{40 d a}+\frac {\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )}{28 d a}+\frac {\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )}{144 d a}}{a^{4}}\) | \(99\) |
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Time = 0.25 (sec) , antiderivative size = 123, normalized size of antiderivative = 0.86 \[ \int \frac {1}{(a+a \cos (c+d x))^5} \, dx=\frac {{\left (8 \, \cos \left (d x + c\right )^{4} + 40 \, \cos \left (d x + c\right )^{3} + 84 \, \cos \left (d x + c\right )^{2} + 100 \, \cos \left (d x + c\right ) + 83\right )} \sin \left (d x + c\right )}{315 \, {\left (a^{5} d \cos \left (d x + c\right )^{5} + 5 \, a^{5} d \cos \left (d x + c\right )^{4} + 10 \, a^{5} d \cos \left (d x + c\right )^{3} + 10 \, a^{5} d \cos \left (d x + c\right )^{2} + 5 \, a^{5} d \cos \left (d x + c\right ) + a^{5} d\right )}} \]
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Time = 2.76 (sec) , antiderivative size = 102, normalized size of antiderivative = 0.71 \[ \int \frac {1}{(a+a \cos (c+d x))^5} \, dx=\begin {cases} \frac {\tan ^{9}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{144 a^{5} d} + \frac {\tan ^{7}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{28 a^{5} d} + \frac {3 \tan ^{5}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{40 a^{5} d} + \frac {\tan ^{3}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{12 a^{5} d} + \frac {\tan {\left (\frac {c}{2} + \frac {d x}{2} \right )}}{16 a^{5} d} & \text {for}\: d \neq 0 \\\frac {x}{\left (a \cos {\left (c \right )} + a\right )^{5}} & \text {otherwise} \end {cases} \]
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Time = 0.21 (sec) , antiderivative size = 107, normalized size of antiderivative = 0.75 \[ \int \frac {1}{(a+a \cos (c+d x))^5} \, dx=\frac {\frac {315 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {420 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {378 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} + \frac {180 \, \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}} + \frac {35 \, \sin \left (d x + c\right )^{9}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{9}}}{5040 \, a^{5} d} \]
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Time = 0.39 (sec) , antiderivative size = 72, normalized size of antiderivative = 0.50 \[ \int \frac {1}{(a+a \cos (c+d x))^5} \, dx=\frac {35 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 180 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 378 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 420 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 315 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{5040 \, a^{5} d} \]
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Time = 14.57 (sec) , antiderivative size = 127, normalized size of antiderivative = 0.89 \[ \int \frac {1}{(a+a \cos (c+d x))^5} \, dx=\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (315\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8+420\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+378\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+180\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+35\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8\right )}{5040\,a^5\,d\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9} \]
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